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unnma 18/06/2020
It arrived in 9 days after I ordered. As it is made of brass and stainless steel, it is heavy despite its small size. I used Coleman's White Gasoline instead of Gasoline because it has less odor and soot and has better startability. As a precaution, I added 5% of Honda 2-stroke oil. I could easily start it with an electric drill with the attached adapter. The throttle stayed slow and the engine ran for about 30 minutes. A good compression was obtained by running around 3 tanks as a break-in operation. It is a very well-made mini OHV engine. By the way, the capacity of both the cooling water hopper and the fuel tank is about 10cc. If the bore 13mm and the stoke 12mm written in the manual are true, I think the engine is 1.6cc instead of 2.6cc.
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  • BG234446222 The Capacity is 1/2 Bore in Quadrat x Strocke. 13:2=6.5 mm 6.5x6.5= 42.25 42.25x13=5.4925cc

    Reply 22/09/2020
  • BG234446222 Correct Capacity

    Reply 22/09/2020
  • BG234446222 Correct Capacity is 6.5x6.5mm=42.25mm2 Area of Piston multiplied by Strocke 42.25x 13= 549.25mm3 or 5.49cc

    Reply 22/09/2020
  • BG234446222 Correct Capacity is 6.5x6.5mm x phix13=1.7246cc

    Reply 22/09/2020
  • BG234446222 Correct Capacity is 6.5x6.5mm x 3.1 x13 = 1.725

    Reply 22/09/2020
  • BG234446222 Correct Capacity is 6.5mm x 6.5mm x 3.14 x13mm = 1.725 cc

    Reply 22/09/2020
  • ChiefH @BG234446222 Wrong answer, the stroke is 12-mm NOT 13-mm recalculate with correct stroke and it willbe 1.6 CC

    Reply 26/10/2020
  • ChiefH @BG234446222 Incorrect result. The stroke is 12-mm NOT 13-mm recalculate using 12-mm and you get 1.6-mm

    Reply 26/10/2020
  • ChiefH I thought the volume of a cylinder was the area of the bore times the length of the stroke.
    In this case the calculation is D^2 times 0.785 times L = (0.13-mm^2)*0.785*0.12-mm which equals 1.591.98 or 1.6-CC

    Reply 26/10/2020
  • ChiefH @BG234446222 The stroke is 12-mm NOT 13-mm your result is incorrect

    Reply 26/10/2020
  • ChiefH The volume of the cylinder is D^2 times 0.785 times L = (0.13-mm^2) * 0,785 *0.12-mm = 1.591-CC, So the displacement is 1.6-CC

    Reply 26/10/2020
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